Find the vertical asymptotes of f(x)=x+1(x−2)2(x+3)f(x) = \frac{x + 1}{(x-2)^2(x+3)}f(x)=(x−2)2(x+3)x+1
x=2x = 2x=2 and x=−3x = -3x=−3
x=2x = 2x=2 only
x=−1x = -1x=−1 and x=−3x = -3x=−3
x=−3x = -3x=−3 only