Find the vertical asymptote of f(x)=x2−1x2−3x+2f(x) = \frac{x^2 - 1}{x^2 - 3x + 2}f(x)=x2−3x+2x2−1.
x=1x = 1x=1
x=2x = 2x=2
x=−1x = -1x=−1
x=0x = 0x=0