Find the vertex, focus, and directrix of the parabola y2−4y−4x+8=0y^2 - 4y - 4x + 8 = 0y2−4y−4x+8=0.
Vertex: (1,2)(1, 2)(1,2), Focus: (2,2)(2, 2)(2,2), Directrix: x=0x = 0x=0
Vertex: (1,2)(1, 2)(1,2), Focus: (0,2)(0, 2)(0,2), Directrix: x=2x = 2x=2
Vertex: (2,1)(2, 1)(2,1), Focus: (3,1)(3, 1)(3,1), Directrix: x=1x = 1x=1