Find the value of xxx such that x+2x−1+x−2x−1=2\sqrt{x+2\sqrt{x-1}} + \sqrt{x-2\sqrt{x-1}} = 2x+2x−1+x−2x−1=2 for x≥2x \ge 2x≥2.
1≤x≤21 \le x \le 21≤x≤2
x=2x = 2x=2
x=3x = 3x=3
No solution