Find the value of xxx in the range [0,π][0, \pi][0,π] for the equation 4cos2(x)−1=04\cos^2(x) - 1 = 04cos2(x)−1=0.
π3\frac{\pi}{3}3π
2π3\frac{2\pi}{3}32π
π6\frac{\pi}{6}6π
Both a and b