Find the value of sin(22.5∘)\sin(22.5^\circ)sin(22.5∘) given cos(45∘)=22\cos(45^\circ) = \frac{\sqrt{2}}{2}cos(45∘)=22.
2−24\sqrt{\frac{2 - \sqrt{2}}{4}}42−2
1+22\sqrt{\frac{1 + \sqrt{2}}{2}}21+2
24\frac{\sqrt{2}}{4}42
12−24\frac{1}{2} - \frac{\sqrt{2}}{4}21−42