Find the value of ppp such that (p,2)(p, 2)(p,2) lies on the circle x2+y2−4x−2y=0x^2 + y^2 - 4x - 2y = 0x2+y2−4x−2y=0.
p=3p = 3p=3 or p=1p = 1p=1
p=2p = 2p=2 or p=0p = 0p=0
p=4p = 4p=4 or p=2p = 2p=2
p=5p = 5p=5 or p=−1p = -1p=−1