Find the value of mmm such that the point (m,2m)(m, 2m)(m,2m) lies on the circle x2+y2−5x−6y+8=0x^2 + y^2 - 5x - 6y + 8 = 0x2+y2−5x−6y+8=0.
m=1m = 1m=1 or m=85m = \frac{8}{5}m=58
m=2m = 2m=2 or m=45m = \frac{4}{5}m=54
m=12m = \frac{1}{2}m=21 or m=4m = 4m=4
m=1m = 1m=1 or m=2m = 2m=2