Find the value of kkk such that the tangent to f(x)=kx2f(x) = kx^2f(x)=kx2 at x=1x=1x=1 passes through (0,−1)(0, -1)(0,−1).
k=0.5k = 0.5k=0.5
k=1k = 1k=1
k=2k = 2k=2
k=−1k = -1k=−1