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Derivativeshard
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Find the value of kkk such that the tangent line to f(x)=kxf(x) = k \sqrt{x}f(x)=kx​ at x=1x=1x=1 is perpendicular to the tangent line to g(x)=x2g(x) = x^2g(x)=x2 at x=1x=1x=1.