Find the value of kkk such that limx→0tan(kx)x=4\lim_{x \to 0} \frac{\tan(kx)}{x} = 4limx→0xtan(kx)=4.
k=2k = 2k=2
k=4k = 4k=4
k=−4k = -4k=−4
k=1k = 1k=1