Find the value of kkk so that g(x)={3x+kx<2x2+1x≥2g(x) = \begin{cases} 3x + k & x < 2 \\ x^2 + 1 & x \geq 2 \end{cases}g(x)={3x+kx2+1x<2x≥2 is continuous at x=2x = 2x=2.
k=−1k = -1k=−1
k=1k = 1k=1
k=5k = 5k=5
k=3k = 3k=3