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Recurrence Relationseasy
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Find the value of a2a_2a2​ for an=3an−1−an−2a_n = 3a_{n-1} - a_{n-2}an​=3an−1​−an−2​ with a0=1,a1=2a_0=1, a_1=2a0​=1,a1​=2.