Find the sum S=∑n=1∞(−1)nn⋅2nS = \sum_{n=1}^{\infty} \frac{(-1)^n}{n \cdot 2^n}S=∑n=1∞n⋅2n(−1)n.
−ln(3/2)-\ln(3/2)−ln(3/2)
−ln(2)-\ln(2)−ln(2)
−ln(3)-\ln(3)−ln(3)
ln(3/2)\ln(3/2)ln(3/2)