Find the sum of the telescoping series ∑n=1∞(1n(n+3))\sum_{n=1}^{\infty} \left(\frac{1}{n(n+3)}\right)∑n=1∞(n(n+3)1). (Hint: use partial fractions)
1118\frac{11}{18}1811
13\frac{1}{3}31
518\frac{5}{18}185
The series diverges