Find the sum 1x2−4+1x2−x−6\frac{1}{x^2-4} + \frac{1}{x^2-x-6}x2−41+x2−x−61.
2x+1(x−2)(x+2)(x−3)\frac{2x+1}{(x-2)(x+2)(x-3)}(x−2)(x+2)(x−3)2x+1
2x+5(x−2)(x+2)(x−3)\frac{2x+5}{(x-2)(x+2)(x-3)}(x−2)(x+2)(x−3)2x+5
2(x−2)(x+2)(x−3)\frac{2}{(x-2)(x+2)(x-3)}(x−2)(x+2)(x−3)2
x+1(x−2)(x+2)(x−3)\frac{x+1}{(x-2)(x+2)(x-3)}(x−2)(x+2)(x−3)x+1