Find the solution to y′=sec2(x)y' = \sec^2(x)y′=sec2(x) given y(0)=0y(0) = 0y(0)=0.
y=tan(x)y = \tan(x)y=tan(x)
y=sec(x)y = \sec(x)y=sec(x)
y=tan(x)+1y = \tan(x) + 1y=tan(x)+1
y=sin(x)y = \sin(x)y=sin(x)