Find the solution to y′=3x2yy' = 3x^2 yy′=3x2y with y(0)=5y(0) = 5y(0)=5.
y=5ex3y = 5e^{x^3}y=5ex3
y=ex3+4y = e^{x^3} + 4y=ex3+4
y=5e3x2y = 5e^{3x^2}y=5e3x2
y=5+x3y = 5+x^3y=5+x3