Find the solution to y′=2xyy' = 2xyy′=2xy with y(0)=1y(0) = 1y(0)=1.
y=ex2y = e^{x^2}y=ex2
y=e2x2y = e^{2x^2}y=e2x2
y=exy = e^xy=ex
y=2exy = 2e^xy=2ex