Find the smallest positive solution to Pell's equation x2−2y2=1x^2 - 2y^2 = 1x2−2y2=1.
(x,y)=(1,0)(x, y) = (1, 0)(x,y)=(1,0)
(x,y)=(2,1)(x, y) = (2, 1)(x,y)=(2,1)
(x,y)=(3,2)(x, y) = (3, 2)(x,y)=(3,2)
No positive integer solutions exist