Find the slope of the tangent line to the curve defined by x2y+y3=10x^2y + y^3 = 10x2y+y3=10 at the point (1,2)(1, 2)(1,2).
−413-\frac{4}{13}−134
−113-\frac{1}{13}−131
−47-\frac{4}{7}−74
−17-\frac{1}{7}−71