Find the slant asymptote of f(x)=3x3−4x+1x2+1f(x) = \frac{3x^3 - 4x + 1}{x^2 + 1}f(x)=x2+13x3−4x+1.
y=3xy = 3xy=3x
y=3x−1y = 3x - 1y=3x−1
y=3x+4y = 3x + 4y=3x+4
y=x+3y = x + 3y=x+3