Find the set of values xxx such that x3−xx+1>0\frac{x^3 - x}{x+1} > 0x+1x3−x>0.
x>1x > 1x>1
x<−1x < -1x<−1 or x>1x > 1x>1
x≠−1x \neq -1x=−1
(−1,0)∪(1,∞)(-1, 0) \cup (1, \infty)(−1,0)∪(1,∞)