Find the set of values for xxx that satisfy x2−16x+5≤0\frac{x^2 - 16}{x + 5} \leq 0x+5x2−16≤0.
x≤−5x \leq -5x≤−5 or −4≤x≤4-4 \leq x \leq 4−4≤x≤4
x<−5x < -5x<−5 or −4≤x≤4-4 \leq x \leq 4−4≤x≤4
−5<x≤−4-5 < x \leq -4−5<x≤−4 or x≥4x \geq 4x≥4
x≤−4x \leq -4x≤−4 or x≥4x \geq 4x≥4