Find the set of all real values xxx such that the inequality x2−4x+3x2+x−2≤0\frac{x^2 - 4x + 3}{x^2 + x - 2} \leq 0x2+x−2x2−4x+3≤0 is satisfied.
(−2,1)∪(1,3](-2, 1) \cup (1, 3](−2,1)∪(1,3]
(−2,3](-2, 3](−2,3]
(−2,1)∪[1,3](-2, 1) \cup [1, 3](−2,1)∪[1,3]
None of the above