Find the second partial derivative fxyf_{xy}fxy for f(x,y)=∫0xsin(t2+y2)dtf(x, y) = \int_0^x \sin(t^2 + y^2) dtf(x,y)=∫0xsin(t2+y2)dt.
−2ycos(x2+y2)-2y \cos(x^2 + y^2)−2ycos(x2+y2)
2ycos(x2+y2)2y \cos(x^2 + y^2)2ycos(x2+y2)
sin(x2+y2)\sin(x^2 + y^2)sin(x2+y2)
2xcos(x2+y2)2x \cos(x^2 + y^2)2xcos(x2+y2)