Find the second derivative of f(x)=xxf(x) = x^xf(x)=xx.
xx(1+lnx)2x^x(1 + \ln x)^2xx(1+lnx)2
xx((1+lnx)2+1x)x^x((1 + \ln x)^2 + \frac{1}{x})xx((1+lnx)2+x1)
xx(1+lnx)x^x(1 + \ln x)xx(1+lnx)
xx(2+lnx)x^x(2 + \ln x)xx(2+lnx)