Find the real values of aaa and bbb such that a+bi=(1+2i)2a + bi = (1 + 2i)^2a+bi=(1+2i)2.
a=−3a = -3a=−3, b=4b = 4b=4
a=1a = 1a=1, b=4b = 4b=4
a=5a = 5a=5, b=4b = 4b=4
a=−3a = -3a=−3, b=2b = 2b=2