Find the range of xxx for x2−5x+6≥0\sqrt{x^2 - 5x + 6} \geq 0x2−5x+6≥0.
x∈(−∞,2]∪[3,∞)x \in ( -\infty, 2 ] \cup [ 3, \infty )x∈(−∞,2]∪[3,∞)
x∈[2,3]x \in [ 2, 3 ]x∈[2,3]
x∈Rx \in \mathbb{R}x∈R
x∈(2,3)x \in ( 2, 3 )x∈(2,3)