Find the radius of convergence of ∑n=1∞x2n4n\sum_{n=1}^{\infty} \frac{x^{2n}}{4^n}∑n=1∞4nx2n.
R=2R = 2R=2
R=4R = 4R=4
R=1R = 1R=1
R=2R = \sqrt{2}R=2