Find the radius of convergence for the series ∑n=1∞n!(2n)!xn\sum_{n=1}^{\infty} \frac{n!}{(2n)!} x^n∑n=1∞(2n)!n!xn.
R=0R = 0R=0
R=1R = 1R=1
R=2R = 2R=2
R=∞R = \inftyR=∞