Find the radius of convergence for the series ∑n=1∞n!xn(2n)!\sum_{n=1}^{\infty} \frac{n! x^n}{(2n)!}∑n=1∞(2n)!n!xn.
R=0R = 0R=0
R=1R = 1R=1
R=4R = 4R=4
R=∞R = \inftyR=∞