Find the radius of convergence for the power series ∑n=1∞(x−2)nn2\sum_{n=1}^{\infty} \frac{(x-2)^n}{n^2}∑n=1∞n2(x−2)n.
R=1R = 1R=1
R=2R = 2R=2
R=∞R = \inftyR=∞
R=0R = 0R=0