Find the radius of convergence for the power series ∑n=1∞(−1)nn23n(x+2)n\sum_{n=1}^{\infty} \frac{(-1)^n n^2}{3^n}(x+2)^n∑n=1∞3n(−1)nn2(x+2)n.
R=3R = 3R=3
R=13R = \frac{1}{3}R=31
R=1R = 1R=1
R=19R = \frac{1}{9}R=91