Find the radius of convergence for f(x)=∑n=0∞2n2xnf(x) = \sum_{n=0}^{\infty} 2^{n^2} x^nf(x)=∑n=0∞2n2xn.
R=1R = 1R=1
R=0R = 0R=0
R=1/2R = 1/2R=1/2
R=∞R = \inftyR=∞