Find the radical axis of the circles x2+y2+2x+4y−3=0x^2 + y^2 + 2x + 4y - 3 = 0x2+y2+2x+4y−3=0 and x2+y2−6x−2y+7=0x^2 + y^2 - 6x - 2y + 7 = 0x2+y2−6x−2y+7=0.
8x+6y−10=08x + 6y - 10 = 08x+6y−10=0
4x+3y−5=04x + 3y - 5 = 04x+3y−5=0
x+3y−5=0x + 3y - 5 = 0x+3y−5=0
2x+4y−1=02x + 4y - 1 = 02x+4y−1=0