Find the polar form of z=−2−2iz = -2 - 2iz=−2−2i.
2\sqrt{2}(\cos(5\pi/4) + i\sin(5\pi/4))
2\sqrt{2}(\cos(3\pi/4) + i\sin(3\pi/4))
4(\cos(5\pi/4) + i\sin(5\pi/4))
2\sqrt{2}(\cos(-3\pi/4) + i\sin(-3\pi/4))