Find the point on the parabola y2=8xy^2 = 8xy2=8x that is closest to the line x−y+3=0x - y + 3 = 0x−y+3=0.
(2,4)(2, 4)(2,4)
(1/2,2)(1/2, 2)(1/2,2)
(2,−4)(2, -4)(2,−4)
(8,8)(8, 8)(8,8)