Find the particular solution to y′=4x3y' = 4x^3y′=4x3 with y(0)=2y(0) = 2y(0)=2.
y=x4+2y = x^4 + 2y=x4+2
y=4x4+2y = 4x^4 + 2y=4x4+2
y=x4+Cy = x^4 + Cy=x4+C
y=4x4y = 4x^4y=4x4