Find the particular solution to dydt=4t\frac{dy}{dt} = 4tdtdy=4t with y(1)=4y(1) = 4y(1)=4.
y=2t2+2y = 2t^2 + 2y=2t2+2
y=4t2y = 4t^2y=4t2
y=2t2+4y = 2t^2 + 4y=2t2+4
y=t2+3y = t^2 + 3y=t2+3