Find the particular solution to dxdt=3t2\frac{dx}{dt} = 3t^2dtdx=3t2 given x(1)=2x(1) = 2x(1)=2.
x=t3+1x = t^3 + 1x=t3+1
x=t3+2x = t^3 + 2x=t3+2
x=3t3+2x = 3t^3 + 2x=3t3+2
x=t3+0x = t^3 + 0x=t3+0