Find the partial derivative fyf_yfy of the function f(x,y)=sin(x2y)f(x,y) = \sin(x^2 y)f(x,y)=sin(x2y).
x2cos(x2y)x^2 \cos(x^2 y)x2cos(x2y)
2xycos(x2y)2xy \cos(x^2 y)2xycos(x2y)
−cos(x2y)-\cos(x^2 y)−cos(x2y)
ycos(x2y)y \cos(x^2 y)ycos(x2y)