Find the length of the common chord of two circles x2+y2=49x^2 + y^2 = 49x2+y2=49 and (x−3)2+y2=16(x-3)^2 + y^2 = 16(x−3)2+y2=16.
218−(49−16)/622\sqrt{18 - (49-16)/6^2}218−(49−16)/62
434\sqrt{3}43
249−25/92\sqrt{49 - 25/9}249−25/9
103/310\sqrt{3}/3103/3