Find the length of the arc of y=23x3/2y = \frac{2}{3}x^{3/2}y=32x3/2 from x=0x=0x=0 to x=3x=3x=3.
143\frac{14}{3}314
163\frac{16}{3}316
555
23(4)3/2−1\frac{2}{3}(4)^{3/2} - 132(4)3/2−1