Find the inverse of f(x)=ln(x+1)+2f(x) = \ln(x+1) + 2f(x)=ln(x+1)+2 for x>−1x > -1x>−1.
f−1(x)=ex−2−1f^{-1}(x) = e^{x-2} - 1f−1(x)=ex−2−1
f−1(x)=ex+2−1f^{-1}(x) = e^{x+2} - 1f−1(x)=ex+2−1
f−1(x)=ex−2+1f^{-1}(x) = e^{x-2} + 1f−1(x)=ex−2+1
f−1(x)=ln(x−2)−1f^{-1}(x) = \ln(x-2) - 1f−1(x)=ln(x−2)−1