Find the inverse of f(x)=x3+2f(x) = \frac{x}{3} + 2f(x)=3x+2.
f−1(x)=3x−6f^{-1}(x) = 3x - 6f−1(x)=3x−6
f−1(x)=3(x−2)f^{-1}(x) = 3(x - 2)f−1(x)=3(x−2)
f−1(x)=3x+2f^{-1}(x) = 3x + 2f−1(x)=3x+2
f−1(x)=x−23f^{-1}(x) = \frac{x - 2}{3}f−1(x)=3x−2