Find the inverse of f(x)=4x+8f(x) = 4x + 8f(x)=4x+8.
f−1(x)=x−84f^{-1}(x) = \frac{x - 8}{4}f−1(x)=4x−8
f−1(x)=x+84f^{-1}(x) = \frac{x + 8}{4}f−1(x)=4x+8
f−1(x)=4x−8f^{-1}(x) = 4x - 8f−1(x)=4x−8
f−1(x)=x4−8f^{-1}(x) = \frac{x}{4} - 8f−1(x)=4x−8