Find the inverse function of f(x)=x+73−2f(x) = \sqrt[3]{x+7} - 2f(x)=3x+7−2.
f−1(x)=(x+2)3−7f^{-1}(x) = (x+2)^3 - 7f−1(x)=(x+2)3−7
f−1(x)=(x−2)3+7f^{-1}(x) = (x-2)^3 + 7f−1(x)=(x−2)3+7
f−1(x)=(x+7)3+2f^{-1}(x) = (x+7)^3 + 2f−1(x)=(x+7)3+2
f−1(x)=x3−5f^{-1}(x) = x^3 - 5f−1(x)=x3−5