Find the inverse function of f(x)=ex+1f(x) = e^{x+1}f(x)=ex+1.
f−1(x)=ln(x)−1f^{-1}(x) = \ln(x) - 1f−1(x)=ln(x)−1
f−1(x)=ln(x)+1f^{-1}(x) = \ln(x) + 1f−1(x)=ln(x)+1
f−1(x)=ln(x−1)f^{-1}(x) = \ln(x - 1)f−1(x)=ln(x−1)
f−1(x)=ex−1f^{-1}(x) = e^{x-1}f−1(x)=ex−1