Find the inverse function of f(x)=2xf(x) = 2^xf(x)=2x.
f−1(x)=log2(x)f^{-1}(x) = \log_2(x)f−1(x)=log2(x)
f−1(x)=12xf^{-1}(x) = \frac{1}{2^x}f−1(x)=2x1
f−1(x)=2−xf^{-1}(x) = 2^{-x}f−1(x)=2−x
f−1(x)=x2f^{-1}(x) = x^2f−1(x)=x2